Word | Frequency | Number of right neighbors | Number of left neighbors | Ratio |
---|---|---|---|---|
El | 10070 | 566 | 8 | 70.7500 |
Els | 3420 | 268 | 4 | 67.0000 |
seva | 4290 | 288 | 5 | 57.6000 |
Però | 1467 | 52 | 1 | 52.0000 |
seves | 988 | 100 | 2 | 50.0000 |
La | 8623 | 556 | 12 | 46.3333 |
En | 5009 | 91 | 2 | 45.5000 |
Les | 2075 | 167 | 4 | 41.7500 |
A | 3855 | 96 | 3 | 32.0000 |
Al | 833 | 62 | 2 | 31.0000 |
Aquest | 1108 | 57 | 2 | 28.5000 |
seus | 1597 | 148 | 6 | 24.6667 |
Una | 1189 | 74 | 3 | 24.6667 |
seu | 4042 | 276 | 12 | 23.0000 |
Per | 2464 | 66 | 3 | 22.0000 |
Un | 1584 | 85 | 4 | 21.2500 |
Ha | 526 | 40 | 2 | 20.0000 |
Es | 828 | 38 | 2 | 19.0000 |
No | 2206 | 74 | 4 | 18.5000 |
Això | 774 | 36 | 2 | 18.0000 |
Word | Frequency | Number of right neighbors | Number of left neighbors | Ratio |
---|---|---|---|---|
creu | 348 | 1 | 17 | 0.0588 |
mena | 214 | 1 | 12 | 0.0833 |
canal | 121 | 1 | 11 | 0.0909 |
haurem | 72 | 1 | 8 | 0.1250 |
allò | 182 | 1 | 8 | 0.1250 |
cicle | 97 | 1 | 8 | 0.1250 |
creuen | 97 | 1 | 8 | 0.1250 |
milions | 1549 | 17 | 128 | 0.1328 |
capaç | 93 | 1 | 7 | 0.1429 |
roda | 304 | 1 | 7 | 0.1429 |
full | 64 | 1 | 7 | 0.1429 |
següents | 68 | 1 | 7 | 0.1429 |
divisió | 68 | 1 | 7 | 0.1429 |
d'abril | 198 | 4 | 27 | 0.1481 |
obligats | 42 | 1 | 6 | 0.1667 |
creiem | 51 | 1 | 6 | 0.1667 |
d'Exteriors | 32 | 1 | 6 | 0.1667 |
eurodiputats | 45 | 1 | 6 | 0.1667 |
pensament | 55 | 1 | 6 | 0.1667 |
d | 216 | 2 | 12 | 0.1667 |
In this subsection, we compute the ratio of the number of right neighbors and the number of left neighbors. Again, we look for words with extreme ratios:
Data for first table:
select word,w.freq,aa.cnt, bb.cnt,aa.cnt/bb.cnt as r from words w, (select w1_id,count(c.w2_id) as cnt from co_n c where w1_id>100 group by w1_id) aa, (select w2_id,count(c.w1_id) as cnt from co_n c where w2_id>100 group by w2_id) bb where w_id=aa.w1_id and aa.w1_id=bb.w2_id order by r desc limit 20;
Diagram data:
select aa.cnt, bb.cnt from (select w1_id,count(c.w2_id) as cnt from co_n c where w1_id>100 group by w1_id) aa, (select w2_id,count(c.w1_id) as cnt from co_n c where w2_id>100 group by w2_id) bb where aa.w1_id=bb.w2_id;
5.1.7.1 Number of NN co-occurrences vs. Frequency I
5.1.7.2 Number of NN co-occurrences vs. Frequency II